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Primary 4 | Maths
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Date Posted: 4 years ago
Views: 294
nos. of pkt
a: 1u
g: 1u + 10
total mass
a: 1u x 0.1 = 0.1u
g: (1u + 10) x 2.9 = 2.9u + 29
0.1u + 2.9u + 29 = 56
1u = 9
total 19 pkts of guavas
.
.
.
a: 1u
g: 1u + 10
total mass
a: 1u x 0.1 = 0.1u
g: (1u + 10) x 2.9 = 2.9u + 29
0.1u + 2.9u + 29 = 56
1u = 9
total 19 pkts of guavas
.
.
.
See 1 Answer
10 packet of guava = 10 x 2.9 = 29 kg
56-29=27
1 package of guava and 1 packet of apples = i2.9+0.1= 3.0kg
Therefore, number of packet of apples = 27/3 = 9 packets
Total guava = 10+9 = 19 packets
Hope this helps
56-29=27
1 package of guava and 1 packet of apples = i2.9+0.1= 3.0kg
Therefore, number of packet of apples = 27/3 = 9 packets
Total guava = 10+9 = 19 packets
Hope this helps
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