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secondary 2 | Maths
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Workins
Date Posted: 5 years ago
Views: 456
given: kx² + 13x - 6 = 0 &
x = -3 is one sol.
u can subst. x = -3 into eqn like this:
k(-3)² + 13(-3) - 6 = 0
=> 9k - 39 - 6 = 0
=> k = 5
u r almost there, u just din subst. x = -3 into 13x to become 13 x (-3)
& the eqn is: 5x² + 13x - 6 = 0
continue the rest , u may , hmmm ?
x = -3 is one sol.
u can subst. x = -3 into eqn like this:
k(-3)² + 13(-3) - 6 = 0
=> 9k - 39 - 6 = 0
=> k = 5
u r almost there, u just din subst. x = -3 into 13x to become 13 x (-3)
& the eqn is: 5x² + 13x - 6 = 0
continue the rest , u may , hmmm ?
See 1 Answer
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Here you go!
Date Posted:
5 years ago
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