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primary 5 | Maths | Angles & Geometry

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##### Tsl

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I don't ready understand about Angles, kindly help me this math question and explaining more how to finding unknown angles. Thank you

Date Posted: 8 months ago
Views: 60
J
8 months ago
From the figure, we know that BD = CD

So angle DBC = angle DCB
(base angles of an isosceles triangle)

angle DBC + angle DCB + angle BDC
= 180° (angle sum of the same triangle)

So sum of the two angles
= 180° - angle DBC
= 180° - 72°
= 108°

Since angle DBC = angle DCB ,
angle DBC = 108° ÷ 2 = 54°

Now, angle DBC = angle BAD + angle BDA
= 54°
(Exterior angle = sum of two interior opposite angles)

And since BA = BD (as marked in the diagram),

angle BAD = angle BDA
(base angles of an isosceles triangle)

So angle BAD = 54° ÷ 2 = 27°
Tsl
8 months ago
Thank you very much for helping and explaining.
J
8 months ago
Welcome

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