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primary 5 | Maths | Angles & Geometry
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Tsl
Tsl

primary 5 chevron_right Maths chevron_right Angles & Geometry chevron_right Singapore

I don't ready understand about Angles, kindly help me this math question and explaining more how to finding unknown angles. Thank you

Date Posted: 4 weeks ago
Views: 18
J
J
4 weeks ago
From the figure, we know that BD = CD

So angle DBC = angle DCB
(base angles of an isosceles triangle)

angle DBC + angle DCB + angle BDC
= 180° (angle sum of the same triangle)


So sum of the two angles
= 180° - angle DBC
= 180° - 72°
= 108°

Since angle DBC = angle DCB ,
angle DBC = 108° ÷ 2 = 54°

Now, angle DBC = angle BAD + angle BDA
= 54°
(Exterior angle = sum of two interior opposite angles)

And since BA = BD (as marked in the diagram),

angle BAD = angle BDA
(base angles of an isosceles triangle)

So angle BAD = 54° ÷ 2 = 27°
Tsl
Tsl
3 weeks ago
Thank you very much for helping and explaining.
J
J
3 weeks ago
Welcome

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Candicenotfromcandyland
Candicenotfromcandyland's answer
83 answers (A Helpful Person)
1st
Ans is 27°.
Hope this helps.
Tsl
Tsl
3 weeks ago
Thank you very much
Tsl
Tsl
3 weeks ago
Thank you very much