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primary 5 | Maths
| Angles & Geometry

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I don't ready understand about Angles, kindly help me this math question and explaining more how to finding unknown angles. Thank you

So angle DBC = angle DCB

(base angles of an isosceles triangle)

angle DBC + angle DCB + angle BDC

= 180° (angle sum of the same triangle)

So sum of the two angles

= 180° - angle DBC

= 180° - 72°

= 108°

Since angle DBC = angle DCB ,

angle DBC = 108° ÷ 2 = 54°

Now, angle DBC = angle BAD + angle BDA

= 54°

(Exterior angle = sum of two interior opposite angles)

And since BA = BD (as marked in the diagram),

angle BAD = angle BDA

(base angles of an isosceles triangle)

So angle BAD = 54° ÷ 2 = 27°

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