Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
primary 5 | Maths
| Angles & Geometry
One Answer Below
Anyone can contribute an answer, even non-tutors.
I don't ready understand about Angles, kindly help me this math question and explaining more how to finding unknown angles. Thank you
Date Posted: 4 years ago
Views: 838
From the figure, we know that BD = CD
So angle DBC = angle DCB
(base angles of an isosceles triangle)
angle DBC + angle DCB + angle BDC
= 180° (angle sum of the same triangle)
So sum of the two angles
= 180° - angle DBC
= 180° - 72°
= 108°
Since angle DBC = angle DCB ,
angle DBC = 108° ÷ 2 = 54°
Now, angle DBC = angle BAD + angle BDA
= 54°
(Exterior angle = sum of two interior opposite angles)
And since BA = BD (as marked in the diagram),
angle BAD = angle BDA
(base angles of an isosceles triangle)
So angle BAD = 54° ÷ 2 = 27°
So angle DBC = angle DCB
(base angles of an isosceles triangle)
angle DBC + angle DCB + angle BDC
= 180° (angle sum of the same triangle)
So sum of the two angles
= 180° - angle DBC
= 180° - 72°
= 108°
Since angle DBC = angle DCB ,
angle DBC = 108° ÷ 2 = 54°
Now, angle DBC = angle BAD + angle BDA
= 54°
(Exterior angle = sum of two interior opposite angles)
And since BA = BD (as marked in the diagram),
angle BAD = angle BDA
(base angles of an isosceles triangle)
So angle BAD = 54° ÷ 2 = 27°
Thank you very much for helping and explaining.
Welcome
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Ans is 27°.
Hope this helps.
Hope this helps.
Date Posted:
4 years ago
Thank you very much
Thank you very much
360 Tutoring Program