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secondary 2 | Maths
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Amanda
Amanda

secondary 2 chevron_right Maths chevron_right Singapore

Pls help! thanks in advance

Date Posted: 3 weeks ago
Views: 27

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LIM TENG SHUEN ERNEST
Lim Teng Shuen Ernest's answer
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Amanda
Amanda
3 weeks ago
How did you get y=-×+c ? then -1=-3+c
LIM TENG SHUEN ERNEST
LIM TENG SHUEN ERNEST
3 weeks ago
As stated, the general equation for a straight line is y = m x + c where m and c are values to be determined.

Apply the gradient formula using x and y values from the two points given to get gradient = -1

m is the gradient, so substitute m = -1 in the general equation to get y = (-1)x + c

All points on a line must satisfy the line equation. Since (3, -1) is a point on the line, we can substitute x = 3, y = -1 into the equation to get

-1 = (-1)(3) + c

We then simplify and solve to get c = 2 and the final line equation y = -x + 2
Amanda
Amanda
3 weeks ago
I see, thank you!