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secondary 4 | A Maths
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Here, eliminating expressions will be good.
Setting x = 1 (x - 1 = 0) eliminates A and B, leaving you to find C.
Setting x = 0 eliminates B, leaving you to find A.
Setting x = some other number helps you
to find the last unknown B.
In recent days I have reduced my frequency of answering posts heavily due to the presence of other helpful tutors and the fact that I have become busier in recent days. You can continue to post questions as usual and someone will answer them. If I have the time to spare, then I will write up my version of the answers.
A third method is very similar to the second, but does not require expansion. This is done at the expense of the prerequisite of strong observation. For example, A must be 2 because the only way we can get the x^3 out is from the (x - 1)^3 term. B and C can be obtained by other methods including my first method.
Actually C can also be found easily because Bx (x - 1) will not contain a constant term. Only the A (x - 1)^3 and the C can spew out the constant terms, but we have found A already. Finding B afterwards is straightforward.
The best way is still to let x = 1, x = 0 and x = 2.
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