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primary 6 | Maths
| Measurement
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I am not sure how to do so please try to help if you know thanks in advance
Those two squares are identical as they have the same length. So each of their lengths = 14cm ÷ 2 = 7cm
Now, the bottom corner square has the same length as the sum of the lengths of the 1 smallest square and the 14-cm square.
So that square's length = 14cm + 7cm
= 21cm
Now the top corner square has the same length as the sum of the lengths of the 14-cm square and the 21-cm square.
So that square's length = 14cm + 21cm
= 35cm
And lastly, the rightmost square where the quadrant is in has the same length as the
sum of the lengths of the 21-cm square and the 35-cm square.
So that square's length = 21cm + 35cm
= 56cm
This length is equal to the radius of the quadrant.
So area of shaded quadrant
= ¼ x 22/7 x 56cm x 56cm
= 2464cm²
Additional info :
Ratio of the square lengths from smallest to biggest
= 1 : 2 : 3 : 5 : 8
This actually forms part of the Fibonacci sequence, which occurs in nature
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