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Question
primary 6 | Maths
| Measurement
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Date Posted: 5 years ago
Views: 323
42-10=32
There's a problem with the question.
Minimum height is 2 cubes high due to that lone cube on the top. For the base, the minimum length is 4 cubes long and same for the breadth as seen from the diagram.
However,
42cm³ can be broken down into its prime factors
42 = 2 x 3 x 7
This is the only possible combination of the 3 dimensions
So there's no way to form a cuboid of 2cm by 3 cm by 7cm if the base is already a minimum of 4 cubes by 4 cubes.
This is based on the presumption that the solid's cubes are undetachable to be rearranged, which is usually the case.
Minimum height is 2 cubes high due to that lone cube on the top. For the base, the minimum length is 4 cubes long and same for the breadth as seen from the diagram.
However,
42cm³ can be broken down into its prime factors
42 = 2 x 3 x 7
This is the only possible combination of the 3 dimensions
So there's no way to form a cuboid of 2cm by 3 cm by 7cm if the base is already a minimum of 4 cubes by 4 cubes.
This is based on the presumption that the solid's cubes are undetachable to be rearranged, which is usually the case.
See 1 Answer
There are 10 cubes so take 42 - 10 = 32
But if you used a calculator It would be a different answer.
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