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primary 6 | Maths
| Algebra
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Date Posted: 5 years ago
Views: 374
E: Average cost is $21
K: Average cost is $25
Pretend all the books that E bought cost $21 and all the books that K bought cost $25.
K bought 1 more book than E
K paid $57 more than E
If K bought one less book, he would have paid $25 less.
Then, E and K would have bought the same number of books and K would have paid $32 more than E.
Each book by K would be $4 more than each book by E.
By calculation, 8 books by K would be 8 x 4 = $32 more than 8 books by E.
So E bought 8 books.
K actually bought 9 books.
K: Average cost is $25
Pretend all the books that E bought cost $21 and all the books that K bought cost $25.
K bought 1 more book than E
K paid $57 more than E
If K bought one less book, he would have paid $25 less.
Then, E and K would have bought the same number of books and K would have paid $32 more than E.
Each book by K would be $4 more than each book by E.
By calculation, 8 books by K would be 8 x 4 = $32 more than 8 books by E.
So E bought 8 books.
K actually bought 9 books.
See 1 Answer
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Hope this helps
Date Posted:
5 years ago
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