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primary 6 | Maths | Algebra
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Easy way

Date Posted: 5 months ago
Views: 51
Eric Nicholas K
Eric Nicholas K
5 months ago
E: Average cost is $21
K: Average cost is $25

Pretend all the books that E bought cost $21 and all the books that K bought cost $25.

K bought 1 more book than E
K paid $57 more than E

If K bought one less book, he would have paid $25 less.

Then, E and K would have bought the same number of books and K would have paid $32 more than E.

Each book by K would be $4 more than each book by E.

By calculation, 8 books by K would be 8 x 4 = $32 more than 8 books by E.

So E bought 8 books.
K actually bought 9 books.

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AC Lim
Ac Lim's answer
3593 answers (A Helpful Person)
Hope this helps
5 months ago