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secondary 2 | Maths

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Pls help having a hard time

I will proceed without the diagram.

For the first one, if you have done the diagram, there will be 3 cases where the sum of the numbers is less than 4 (namely 1 1, 1 2 and 2 1) and 33 cases where the sum of the numbers is 4 or more. So the possibility that the numbers add up to at least 4 is 33/36.

For the second one, you will need to draw a second possibility diagram, this time for the products of the two numbers on the dice.

There are 3 cases in which the product is 24 or more, namely 4 x 6, 5 x 5 and 6 x 4. All other 33 cases result in products lower than 24.

So the possibility that the numbers multiply to less than 24 is 33/36 = 11/12.

The third one is straightforward. There are only six cases in which both numbers are the same, namely 1 1 and so on up to 6 6. The other 30 cases allow for different numbers being multiplied together. So the possibility that the two colours are different is 30/36.

Did not account for 5 and 5 in my working above, but that's about the only fault there.

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