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secondary 4 | A Maths
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Hello, just part i will do!and is b = -2?
Date Posted: 4 years ago
Views: 227
When x = 0, y = ln 2
Sub thie into equation y = log a (b - x)
ln 2 = loga(b)
ln 2 / 1 = ln b / ln a
ln 2 / ln e = ln b / ln a
Comparing the terms, b = 2, a = e
Or
ln 2 = loga(b)
log e (2) = log a (b)
So comparing, a = e, b = 2
When x = c , y = ln 5,
ln 5 = log e (2 - c)
ln 5 = ln (2 - c)
5 = 2 - c
c = -3
Sub thie into equation y = log a (b - x)
ln 2 = loga(b)
ln 2 / 1 = ln b / ln a
ln 2 / ln e = ln b / ln a
Comparing the terms, b = 2, a = e
Or
ln 2 = loga(b)
log e (2) = log a (b)
So comparing, a = e, b = 2
When x = c , y = ln 5,
ln 5 = log e (2 - c)
ln 5 = ln (2 - c)
5 = 2 - c
c = -3
Thank you :)
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Good afternoon Candice! Here are my workings for this question.
Date Posted:
4 years ago
Thank you :D
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