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primary 5 | Maths
| Fractions
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Date Posted: 4 years ago
Views: 208
There are 3 equal pieces cut out from Rope Q and Rope R.
Rope Q is 1.5 m in length.
Each mini-piece cut from Rope R is 0.4 m more than each mini-piece cut from Rope Q. There are three sets of mini-pieces, so Rope R must have been 0.4 x 3 = 1.2 m longer than Rope Q.
Length of Rope R
= 1.5 + 1.2
= 2.7 m
= 27/10 m
= 2 7/10 m (mixed fraction)
Rope Q is 1.5 m in length.
Each mini-piece cut from Rope R is 0.4 m more than each mini-piece cut from Rope Q. There are three sets of mini-pieces, so Rope R must have been 0.4 x 3 = 1.2 m longer than Rope Q.
Length of Rope R
= 1.5 + 1.2
= 2.7 m
= 27/10 m
= 2 7/10 m (mixed fraction)
A second idea is this.
Since Rope Q is 1.5 m long, each piece cut out from Rope Q is 1.5 / 3 = 0.5 m long, where / is my division symbol.
Since each piece cut out from Rope R is 0.4 m longer than each piece cut out from Rope Q,
Length of each piece cut out from Rope R
= 0.5 + 0.4
= 0.9 m
Length of Rope R
= 0.9 x 3
= 2.7 m
as before.
Since Rope Q is 1.5 m long, each piece cut out from Rope Q is 1.5 / 3 = 0.5 m long, where / is my division symbol.
Since each piece cut out from Rope R is 0.4 m longer than each piece cut out from Rope Q,
Length of each piece cut out from Rope R
= 0.5 + 0.4
= 0.9 m
Length of Rope R
= 0.9 x 3
= 2.7 m
as before.
See 1 Answer
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Ans is 2.7 m. Hope this helps
Date Posted:
4 years ago
Is good
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