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junior college 2 | H3 Maths
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pls help
0 < |x - a| < δ ⇒ |f(x) - c| < ε
So |c - c| < ε
|0| < ε → 0 < ε
So 0 < ε no matter which δ you choose.
See 1 Answer
You can just let δ = a positive number which is ≤ ε . No matter which δ you choose here, ε always > 0. So |c - c| always < ε
The proof for the limit of a constant function is done differently from the usual
It is that simple