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Primary 4 | Maths
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Date Posted: 7 years ago
Views: 517
This is a multiples question, so we need to calculate in multiples of 7, and add a remainder of 4 to each multiple.
7 (+4) = 11
14 (+4) = 18
21 (+4) = 25
Thus the smallest even no. is 18 cause the other two are odd numbers.
7 (+4) = 11
14 (+4) = 18
21 (+4) = 25
Thus the smallest even no. is 18 cause the other two are odd numbers.
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Hope this helps :)
Date Posted:
7 years ago
Thank you.
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