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Question
primary 6 | Maths
| Measurement
2 Answers Below
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Date Posted: 4 years ago
Views: 329
(a) 8M=12S, so 2M=3S. The pail can fit 12S. Now already have 3S (2M), so can still fit 12-3=9S
(b)1L=2M+1S, so 10L=20M+10S.
10L+10M+10S=30M+20S
2M=3S, so 30M=45S
45S+20S=65S. One pail can fit 12S. so 65/12=5(5/12). Total needs 6 pails to fit 10L, 10M and 10S
(b)1L=2M+1S, so 10L=20M+10S.
10L+10M+10S=30M+20S
2M=3S, so 30M=45S
45S+20S=65S. One pail can fit 12S. so 65/12=5(5/12). Total needs 6 pails to fit 10L, 10M and 10S
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8 and 12 common multiple = 24. Therefore let the pail = 24u. Hope this helps
Date Posted:
4 years ago
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