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secondary 4 | E Maths
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Jason
Jason

secondary 4 chevron_right E Maths chevron_right Singapore

Math question from BMAT

Date Posted: 1 month ago
Views: 18
J
J
1 month ago
Biggest circle - 2nd biggest + 2nd smallest - smallest


π(4d/2)² - π(3d/2)² + π(2d/2)² - π(d/2)²

= 4d²π - 9/4 d²π + d²π - ¼d²π

= πd²(4 - 9/4 + 1 - ¼)

= πd² (5/2)

= 5/2 πd²

Option A

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Bern Ong @ 88Tuition
Bern Ong @ 88tuition's answer
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Visualisation is a skill. Train well and you can attempt countless questions. You can do it;)
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DAI BIN
Dai Bin's answer
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