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Question
primary 6 | Maths
| Speed
2 Answers Below
Anyone can contribute an answer, even non-tutors.
Please help to solve and explain. The circular track examples are difficult to explain. Thank you
Date Posted: 4 years ago
Views: 463
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Bus X
Distance 55 km
Time 50 mins
Speed 55÷50 = 1.1km/min
Given the meet every 30 mins.
In 30 bus X travel 1.1×30=33km
Bus Y travelled 22 km in 30 mins.
The different distance between them is 11 km.
To meet again at interchange, they will need to meet 55÷ 11 = 5 times.
1 time meet take 30 mins,
5 times meet take 150 mins = 2.5 hours.
Therefore, they will meet again at 6.30am + 2 hour 30 mins = 9.00am.
Time next meet is 9.00am
Hope this helps.
Distance 55 km
Time 50 mins
Speed 55÷50 = 1.1km/min
Given the meet every 30 mins.
In 30 bus X travel 1.1×30=33km
Bus Y travelled 22 km in 30 mins.
The different distance between them is 11 km.
To meet again at interchange, they will need to meet 55÷ 11 = 5 times.
1 time meet take 30 mins,
5 times meet take 150 mins = 2.5 hours.
Therefore, they will meet again at 6.30am + 2 hour 30 mins = 9.00am.
Time next meet is 9.00am
Hope this helps.
done
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The diagram for better visualization. Hope this helps
Date Posted:
4 years ago
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