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Exterior Angle at Q = 212-180 = 32 deg
Sum of all exterior angles = 360 deg
Let n be the total number of exterior angles or number of sides.
32 + (n-1)(41) = 360
41n - 41 = 360 - 32
41n = 360 - 32 + 41
41n = 369
n = 369/41 = 9
Sum of all exterior angles = 360 deg
Let n be the total number of exterior angles or number of sides.
32 + (n-1)(41) = 360
41n - 41 = 360 - 32
41n = 360 - 32 + 41
41n = 369
n = 369/41 = 9