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Question
primary 6 | Maths
| Measurement
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Pls help ans
after 9.30 am
16 km
= 10 km + 6 km
fare
= $2.50 + $0.10 x 10 000/200 + $0.10 x 6000/150
= $2.50 + $5 + $4
= $11.50
(b)
before 9.30 am
fare = $18
= $2.50 + $2.00 + $0.10 x 10 000/200 + $0.10 x 300u/150
= $2.50 + $2 + $5 + $0.20u
= $9.50 + $0.20u
18 = 9.50 + 0.20u
u = 42.5
max. dist.
= 10 km + 42.5 x 300 m
= 10 km + 12.75 km
= 22.75 km
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