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Question
primary 6 | Maths
| Measurement
One Answer Below
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EF = HF = GF = radius
so
triangle HFE &
triangle GFH are isosceles triangles
&
1. angle FHE + angle FHG = angle EHG
2. angle EFH + angle HFG = 90 deg
3. angle FHE = angle FEH
4. angle FHG = angle FGH
5. angle FHE + angle FEH + angle EFH = 180 deg
6. angle FHG + angle FGH + angle HFG = 180 deg
hence,
angle FHE + angle FEH + angle EFH + angle FHG + angle FGH + angle HFG = 180 + 180 = 360 deg
angle FHE + angle FHE + angle EFH + angle FHG + angle FHG + angle HFG = 360 deg
2 x angle FHE + angle EFH + 2 x angle FHG + angle HFG = 360 deg
2 x angle FHE + 2 x angle FHG + angle EFH + angle HFG = 360 deg
2 x angle FHE + 2 x angle FHG + 90 deg = 360 deg
2 x angle FHE + 2 x angle FHG = 270 deg
2 x (angle FHE + angle FHG) = 270 deg
rem:
1. angle FHE + angle FHG = angle EHG
thus,
2 x (angle EHG) = 270 deg
angle EHG = 270/2 = 135 deg
...
See 1 Answer
You must think out of the box like finding the sum of angle of (a+b) instead of finding a and b individually.