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primary 6 | Maths
| Measurement
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Date Posted: 5 years ago
Views: 487
There are 5 equal longer sides and 5 equal shorter sides.
5 equal longer sides + 5 equal shorter sides = 150cm
You can group them into 5 equal sets, each having 1 shorter and 1 longer side.
So 5 sets = 150cm
1 set = 150cm ÷ 5 = 30cm
Notice that ABCFE is just 1 longer + 1 shorter side
So ABCFE = 30cm
You don't have to assume any lengths to solve the question. And you shouldn't do so as no lengths are given. It will be considered mathematically incorrect.
5 equal longer sides + 5 equal shorter sides = 150cm
You can group them into 5 equal sets, each having 1 shorter and 1 longer side.
So 5 sets = 150cm
1 set = 150cm ÷ 5 = 30cm
Notice that ABCFE is just 1 longer + 1 shorter side
So ABCFE = 30cm
You don't have to assume any lengths to solve the question. And you shouldn't do so as no lengths are given. It will be considered mathematically incorrect.
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Cannot assume that the longer sides are 20cm and the shorter sides are 10cm, as it is not given in the question. This is mathematically incorrect
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