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Secondary 1 | Maths
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Date Posted: 4 years ago
Views: 273
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Hi Amelia! Here are my workings for this question. Remember that the sum of all the exterior angles in a polygon is 360 deg.
The first two exterior angles have a value of 35 deg and 72 deg.
This means that the sum of the remaining (n - 2) exterior angles
= 360 - 35 - 72
= 325 - 72
= 253
The remaining exterior angles are 23 each, so the number of such exterior angles
= 253/23
= 11
Add this to the starting two exterior angles and we have the total number of sides of the polygon = 11 + 2 = 13 so n = 13.
The first two exterior angles have a value of 35 deg and 72 deg.
This means that the sum of the remaining (n - 2) exterior angles
= 360 - 35 - 72
= 325 - 72
= 253
The remaining exterior angles are 23 each, so the number of such exterior angles
= 253/23
= 11
Add this to the starting two exterior angles and we have the total number of sides of the polygon = 11 + 2 = 13 so n = 13.
Date Posted:
4 years ago
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