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Cube B's sides are 25% longer. So if Cube A sides are taken as 100%, Cube B's will be 125% of Cube A's.

100% → 4cm

125% → 4cm x 125/100 = 4cm x 5/4 = 5cm

So Cube B has sides that are 5cm long

Or

25% longer means 1/4 longer. If Cube A's sides are 4 units long, then Cube B's sides are 1 unit longer

4 units = 4cm

1 unit = 1cm

Cube B 's sides = 1 unit + 4 units = 5 units

= 5 x 1cm = 5cm

Volume of Cube B = 5cm x 5cm x 5cm = 125cm³

b)

Volume of Cube A = 4cm x 4cm x 4cm = 64cm³

Total of cube A, B and C = 135cm³ x 3 = 405cm³

So volume of Cube C

= 405cm³ - 125cm³ - 64cm³ = 216cm³

216cm³ = 6cm x 6cm x 6cm

So Cube C has sides 6cm long.

6cm - 4cm = 2cm

So Cube C's sides are 2cm longer than Cube A's sides.

2cm/4cm x 100% = ½ x 100% = 50%

Cube C's sides are 50% longer than Cube A's sides.

100% → 4cm

125% → 4cm x 125/100 = 4cm x 5/4 = 5cm

So Cube B has sides that are 5cm long

Or

25% longer means 1/4 longer. If Cube A's sides are 4 units long, then Cube B's sides are 1 unit longer

4 units = 4cm

1 unit = 1cm

Cube B 's sides = 1 unit + 4 units = 5 units

= 5 x 1cm = 5cm

Volume of Cube B = 5cm x 5cm x 5cm = 125cm³

b)

Volume of Cube A = 4cm x 4cm x 4cm = 64cm³

Total of cube A, B and C = 135cm³ x 3 = 405cm³

So volume of Cube C

= 405cm³ - 125cm³ - 64cm³ = 216cm³

216cm³ = 6cm x 6cm x 6cm

So Cube C has sides 6cm long.

6cm - 4cm = 2cm

So Cube C's sides are 2cm longer than Cube A's sides.

2cm/4cm x 100% = ½ x 100% = 50%

Cube C's sides are 50% longer than Cube A's sides.

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