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secondary 4 | E Maths
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Nabanita bose
Nabanita Bose

secondary 4 chevron_right E Maths chevron_right Singapore

I’m confused?

Date Posted: 4 years ago
Views: 664

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Hor Kuok Theng
Hor Kuok Theng's answer
20 answers (A Helpful Person)
1st
It is essentially the same as any other factorization problem, just with the usual order reversed.
J
J
4 years ago
Either square root could take the negative, not just the square root of 9x² i.e it can be equivalently written as (3x - 2y)² as well.
So it's not really correct to say that 'since 4y² is positive, the factor producing 9x² is negative'. Rather, whichever square root you take as positive makes the other negative.
Hor Kuok Theng
Hor Kuok Theng
4 years ago
Thanks for the comment, J!

Factorizing polynomials may lead to more than one correct solution. In this case, I used the word know with the same connotation of "We can deduce, for at least one possible solution"

If that offended you, I do apologize!
J
J
4 years ago
Oh I see. No offence caused, just clarifying
Step by step factorisation :

9x² - 12xy + 4y²
= 9x² - 6xy + 4y² - 6xy (split up the -12xy equally into 2)
= 3x(3x - 2y) + 2y(2y - 3x)
= 3x(3x - 2y) - 2y(-(2y - 3x))
= 3x(3x - 2y) - 2y(3x - 2y)
= (3x - 2y)(3x - 2y)
= (3x - 2y)²

Alternatively, you could do this :
9x² - 12xy + 4y²
= (3x)² - 2(3x)(2y) + (2y)²
Notice that this is in the form a² - 2ab + b², where a = 3x and b = 2y
Since (a - b)² = a² - 2ab + b²,
9x² - 12xy + 4y²
= (3x)² - 2(3x)(2y) + (2y)²
= (3x - 2y)²
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J
J's answer
1022 answers (A Helpful Person)