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primary 5 | Maths | Angles & Geometry
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Sarah Wong
Sarah Wong

primary 5 chevron_right Maths chevron_right Angles & Geometry chevron_right Singapore

How would u do it??

Date Posted: 3 weeks ago
Views: 16
snell
Snell
3 weeks ago
angle AOB = angle DOE
&
given angle BOC = angle AOF

so
angle AOB + angle AOF = 152/2
= 76 deg



angle EOF + angle AOB + angle AOF = 180 deg

angle EOF + 76 deg = 180 deg

angle EOF = 180-76 = 104 deg


...
J
J
3 weeks ago
The reason why you can divide by 2 is that

AOF + AOB = BOC + DOE

So 152° is equal to two sets of AOF and AOB.

So AOF + AOB = 152 ÷ 2 = 76 °

EOF = 180° - AOF - AOB
= 180° - 76°
= 104°
(sum of angles on straight line BE)


Alternatively,

You can also use line AD to find.


Since AOB = DOE,
then AOF + DOE = AOF + AOB = 76°

EOF = 180° - AOF - DOE
= 180° - 76°
= 104°
(sum of angles on straight line AD)



And you'll realise COD = EOF

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Rachel
Rachel's answer
19 answers (A Helpful Person)
1st
don't give up!!!!!!!!
J
J
3 weeks ago
AOB and EOD should be labelled as same angles , but with a separate colour instead of having only the purple one which only suggests that all add to 152°
Sarah Wong
Sarah Wong
3 weeks ago
Thank u so much!!!