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primary 5 | Maths
| Angles & Geometry
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How would u do it??
Date Posted: 4 years ago
Views: 269
angle AOB = angle DOE
&
given angle BOC = angle AOF
so
angle AOB + angle AOF = 152/2
= 76 deg
angle EOF + angle AOB + angle AOF = 180 deg
angle EOF + 76 deg = 180 deg
angle EOF = 180-76 = 104 deg
...
&
given angle BOC = angle AOF
so
angle AOB + angle AOF = 152/2
= 76 deg
angle EOF + angle AOB + angle AOF = 180 deg
angle EOF + 76 deg = 180 deg
angle EOF = 180-76 = 104 deg
...
The reason why you can divide by 2 is that
AOF + AOB = BOC + DOE
So 152° is equal to two sets of AOF and AOB.
So AOF + AOB = 152 ÷ 2 = 76 °
EOF = 180° - AOF - AOB
= 180° - 76°
= 104°
(sum of angles on straight line BE)
Alternatively,
You can also use line AD to find.
Since AOB = DOE,
then AOF + DOE = AOF + AOB = 76°
EOF = 180° - AOF - DOE
= 180° - 76°
= 104°
(sum of angles on straight line AD)
And you'll realise COD = EOF
AOF + AOB = BOC + DOE
So 152° is equal to two sets of AOF and AOB.
So AOF + AOB = 152 ÷ 2 = 76 °
EOF = 180° - AOF - AOB
= 180° - 76°
= 104°
(sum of angles on straight line BE)
Alternatively,
You can also use line AD to find.
Since AOB = DOE,
then AOF + DOE = AOF + AOB = 76°
EOF = 180° - AOF - DOE
= 180° - 76°
= 104°
(sum of angles on straight line AD)
And you'll realise COD = EOF
See 1 Answer
done
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clear
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don't give up!!!!!!!!
Date Posted:
4 years ago
AOB and EOD should be labelled as same angles , but with a separate colour instead of having only the purple one which only suggests that all add to 152°
Thank u so much!!!
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