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Question
primary 6 | Maths
| Fractions
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Date Posted: 4 years ago
Views: 272
method 1
6A
total: 10u
g: (10u - 4)/2 = 5u - 2
b: 5u - 2 + 4 = 5u + 2
6B
total: 10u
g: (10u - 16)/2 = 5u - 8
b: 5u - 8 + 16 = 5u + 8
total g = 10u - 10
8 x (10u - 10) = 3 x 20u
u = 4
total boys = 10x4 + 10 = 50
OR
method 2
6A
g: u
b: u + 4
total: 2u + 4
6B
g: (2u+4 - 16)/2 = u - 6
b: u - 6 +16 = u + 10
total: 2u + 4
6A + 6B = 4u + 8
total g in both class = 2u - 6
8 x (2u - 6) = 3 x (4u + 8)
u = 18
total boys = 2x18 + 14 = 50
...
6A
total: 10u
g: (10u - 4)/2 = 5u - 2
b: 5u - 2 + 4 = 5u + 2
6B
total: 10u
g: (10u - 16)/2 = 5u - 8
b: 5u - 8 + 16 = 5u + 8
total g = 10u - 10
8 x (10u - 10) = 3 x 20u
u = 4
total boys = 10x4 + 10 = 50
OR
method 2
6A
g: u
b: u + 4
total: 2u + 4
6B
g: (2u+4 - 16)/2 = u - 6
b: u - 6 +16 = u + 10
total: 2u + 4
6A + 6B = 4u + 8
total g in both class = 2u - 6
8 x (2u - 6) = 3 x (4u + 8)
u = 18
total boys = 2x18 + 14 = 50
...
See 1 Answer
done
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My answer is 50.Hope my method is easy to understand.
Date Posted:
4 years ago
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