## Question

primary 5 | Maths | Whole Numbers

Anyone can contribute an answer, even non-tutors.

##### Javier

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Hello! Mother help maybe? BTW, Dis is Paper 2... So it's quite difficult tho... LoL

Date Posted: 11 months ago
Views: 52
Snell
11 months ago
4 adults + 5 children = 259
12 adults + 15 children = 777

3 adults + 6 children = 246
12 adults + 24 children = 984

24-15 children = 984 - 777
9 children = 207
1 child = \$23

admission cost for 1 child is \$23

...
J
11 months ago
Alternative method

\$259 for 4 adult and 5 children tickets
\$246 for 3 adult tickets and 6 children tickets

Notice that there are 9 people for both cases. Both cases have 5 children and 3 adults tickets in common.

So difference between the price for the two cases is just the difference between 1 child and 1 adult ticket.

Difference = \$259 - \$246 = \$13

So 1 adult ticket cost \$13 more than 1 child ticket.

Change the adult tickets to children tickets by subtracting \$13 from each case.

\$259 for 4 adult 5 children :

\$259 - \$13 x 4 = \$259 - \$52 = \$207

So \$208 is the cost of 9 child tickets.

1 child ticket = \$207 ÷ 9 = \$23

Or

\$246 for 3 adults 6 children

\$246 - \$13 x 3 = \$246 - \$39 = \$207

Same as above,
\$207 is the cost of 9 child tickets.

1 child ticket = \$207 ÷ 9 = \$23