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## Question

primary 5 | Maths
| Whole Numbers

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Hello! Mother help maybe? BTW, Dis is Paper 2... So it's quite difficult tho... LoL

12 adults + 15 children = 777

3 adults + 6 children = 246

12 adults + 24 children = 984

24-15 children = 984 - 777

9 children = 207

1 child = $23

admission cost for 1 child is $23

...

$259 for 4 adult and 5 children tickets

$246 for 3 adult tickets and 6 children tickets

Notice that there are 9 people for both cases. Both cases have 5 children and 3 adults tickets in common.

So difference between the price for the two cases is just the difference between 1 child and 1 adult ticket.

Difference = $259 - $246 = $13

So 1 adult ticket cost $13 more than 1 child ticket.

Change the adult tickets to children tickets by subtracting $13 from each case.

$259 for 4 adult 5 children :

Convert the 4 adult tickets,

$259 - $13 x 4 = $259 - $52 = $207

So $208 is the cost of 9 child tickets.

1 child ticket = $207 ÷ 9 = $23

Or

$246 for 3 adults 6 children

Convert the 3 adult tickets,

$246 - $13 x 3 = $246 - $39 = $207

Same as above,

$207 is the cost of 9 child tickets.

1 child ticket = $207 ÷ 9 = $23

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