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Question
primary 5 | Maths
| Whole Numbers
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Hello! Mother help maybe? BTW, Dis is Paper 2... So it's quite difficult tho... LoL
12 adults + 15 children = 777
3 adults + 6 children = 246
12 adults + 24 children = 984
24-15 children = 984 - 777
9 children = 207
1 child = $23
admission cost for 1 child is $23
...
$259 for 4 adult and 5 children tickets
$246 for 3 adult tickets and 6 children tickets
Notice that there are 9 people for both cases. Both cases have 5 children and 3 adults tickets in common.
So difference between the price for the two cases is just the difference between 1 child and 1 adult ticket.
Difference = $259 - $246 = $13
So 1 adult ticket cost $13 more than 1 child ticket.
Change the adult tickets to children tickets by subtracting $13 from each case.
$259 for 4 adult 5 children :
Convert the 4 adult tickets,
$259 - $13 x 4 = $259 - $52 = $207
So $208 is the cost of 9 child tickets.
1 child ticket = $207 ÷ 9 = $23
Or
$246 for 3 adults 6 children
Convert the 3 adult tickets,
$246 - $13 x 3 = $246 - $39 = $207
Same as above,
$207 is the cost of 9 child tickets.
1 child ticket = $207 ÷ 9 = $23
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