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secondary 4 | A Maths
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michelle wong
Michelle Wong

secondary 4 chevron_right A Maths chevron_right Singapore

please help thankyouu

Date Posted: 2 months ago
Views: 22
J
J
2 months ago
³√a / a-¹ ÷ √a³

= a^⅓ × a¹ ÷ (a³)^½

= a^⅓ × a¹ ÷ a^³⁄²

= a^(⅓ + 1 - 3/2)

= a^(-1/6)

= 1/( a^(1/6) )

= 1/6√a

(Note the 6√ here is written on paper like ³√. It's a superscript. My keyboard doesn't have superscript for 6 so couldn't type it like ³

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Arnold K H Tan
Arnold K H Tan's answer
880 answers (A Helpful Person)
1st
Note that the question is worth 6 marks, so its very likely that you cannot leave a surd term in the denominator, especially for Amaths.