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primary 5 | Maths
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Date Posted: 4 years ago
Views: 188
cost
3 b: $24
8 b: $64
8 d + 3 b = 8 d + 24
3 d + 8 b = 3 d + 64
8 d + 24 = 3 d + 64 + 20
d = 60/5 = $12
1 dress costs $12
...
3 b: $24
8 b: $64
8 d + 3 b = 8 d + 24
3 d + 8 b = 3 d + 64
8 d + 24 = 3 d + 64 + 20
d = 60/5 = $12
1 dress costs $12
...
Non algebra method :
Compare the two cases :
①8 dresses and 3 blouses
②3 dresses and 8 blouses.
Notice that there are 3 blouses and 3 dresses in common.
What is different is just 5 blouses and 5 dresses.
So 5 dresses cost $20 more than 5 blouses.
$20 ÷ 5 = $4
1 dress cost $4 than 1 blouse.
Cost of a dress = $8 + $4 = $12
Compare the two cases :
①8 dresses and 3 blouses
②3 dresses and 8 blouses.
Notice that there are 3 blouses and 3 dresses in common.
What is different is just 5 blouses and 5 dresses.
So 5 dresses cost $20 more than 5 blouses.
$20 ÷ 5 = $4
1 dress cost $4 than 1 blouse.
Cost of a dress = $8 + $4 = $12
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Date Posted:
4 years ago
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