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secondary 2 | Science
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Date Posted: 5 years ago
Views: 1477
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*note: let the pt (or node) on top of A & 30-ohm resistor be O.
Explanation 1:
the voltage (or p.d.) across OB is 6 V (same as the dry cells of 6 V).
the resistance across OB is 30+30 = 60 ohms ; the resistance across AB is 30 ohms, which is half of that across OB.
hence by proportion, the voltage or p.d. across AB is half of that across OB or half of 6 V.
hence p.d. across A & B is 3.0 V.
Explanation 2:
the current flowing through the branch of OB is 6/(30+30) = 6/60 = 0.1 A.
since the current thru' OB is equal to the curren flowing thru' AB (= 0.1 A), the p.d. across AB = I x R = 0.1 x 30 = 3.0 V.
Explanation 3
(sec 2 may not hv learnt it):
the potential at pt A is 3.0 V & the potential at pt B is 0 V.
hence, the potential difference across A & B is (3 - 0) = 3.0 V.
...
*note: let the pt (or node) on top of A & 30-ohm resistor be O.
Explanation 1:
the voltage (or p.d.) across OB is 6 V (same as the dry cells of 6 V).
the resistance across OB is 30+30 = 60 ohms ; the resistance across AB is 30 ohms, which is half of that across OB.
hence by proportion, the voltage or p.d. across AB is half of that across OB or half of 6 V.
hence p.d. across A & B is 3.0 V.
Explanation 2:
the current flowing through the branch of OB is 6/(30+30) = 6/60 = 0.1 A.
since the current thru' OB is equal to the curren flowing thru' AB (= 0.1 A), the p.d. across AB = I x R = 0.1 x 30 = 3.0 V.
Explanation 3
(sec 2 may not hv learnt it):
the potential at pt A is 3.0 V & the potential at pt B is 0 V.
hence, the potential difference across A & B is (3 - 0) = 3.0 V.
...
See 2 Answers
Hi,
The fundamental principle to use here is Ohm's Law: V= IR
Total Voltage = 6V
We have two 30Ohms resistors connected in series. Thus, total resistance = 60Ohms.
Total Current through 30Ohm resistors = 6/60A
Voltage across 30Ohm resistor is (6/60)*30 = 3V
The fundamental principle to use here is Ohm's Law: V= IR
Total Voltage = 6V
We have two 30Ohms resistors connected in series. Thus, total resistance = 60Ohms.
Total Current through 30Ohm resistors = 6/60A
Voltage across 30Ohm resistor is (6/60)*30 = 3V
done
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