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Question
primary 5 | Maths
| Area & Volume
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Date Posted: 4 years ago
Views: 387
Area of the largest rectangle (which is the 12 cm by 12 cm square, in fact)
= 12 x 12
= 144 cm^2
Area of left side unshaded region (that triangle with 4 cm and 12 cm)
=1/2 x 4 x 12
= 24 cm^2
Area of top right unshaded region (that triangle with 4 cm and 8 cm)
= 1/2 x 4 x 8
= 16 cm^2
Area of bottom unshaded region (that triangle with 8 cm and 12 cm)
= 1/2 x 8 x 12
= 48 cm^2
Area of shaded triangle
= 144 - 24 - 16 - 48
= 56 cm^2
= 12 x 12
= 144 cm^2
Area of left side unshaded region (that triangle with 4 cm and 12 cm)
=1/2 x 4 x 12
= 24 cm^2
Area of top right unshaded region (that triangle with 4 cm and 8 cm)
= 1/2 x 4 x 8
= 16 cm^2
Area of bottom unshaded region (that triangle with 8 cm and 12 cm)
= 1/2 x 8 x 12
= 48 cm^2
Area of shaded triangle
= 144 - 24 - 16 - 48
= 56 cm^2
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Date Posted:
4 years ago
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