## Ask Singapore Homework?

Upload a photo of a Singapore homework and someone will email you the solution for free.

### See 3 Answers

*done*{{ upvoteCount }} Upvotes

*clear*{{ downvoteCount * -1 }} Downvotes

First one

Date Posted:
1 month ago

log3(x) - 1 = log(8x³)

log3(x) - log3(3) = log(8x³)

log3(x/3) = log(8x³)

So

x/3 = 8x³

x = 24x³

24x³ - x = 0

x(24x² - 1) = 0

x(√24 x + 1)(√24 x - 1) = 0

(using property a² - b² = (a + b)(a - b) )

x = 0 or √24 x = 1 or √24 x = -1

(x = 0 is rejected as log3(x) is undefined for x ≤ 0 for real values of log3(x) )

x = 1/√24 or or x = -1/√24 (x = -1/√24 is rejected for the same reason as above)

x = √24/24

x = √(4 x 6) / 24

x = 2√6 / 24

x = √6 /12

But I presume that here is ok because the missing roots are always zero roots and log(any) 0 is undefined.

i.e all roots should be found first, then rejection is done if required

Hmmm...interesting point

But that would result in deduction of marks. Because x = -1/√24 are also valid roots of the equation 24x² - 1 = 0. Likewise for x = 0 for the equation 24x³ - x = 0.

it's because the original equation had the log3( ), so in the context of the question , we reject them.

There is a need to find the negative root and show why the negative root is rejected. Since the zero root carries equal weight as the other roots, it must also be shown that it exists but is rejected.

*done*{{ upvoteCount }} Upvotes

*clear*{{ downvoteCount * -1 }} Downvotes

Second one

Date Posted:
1 month ago

*done*{{ upvoteCount }} Upvotes

*clear*{{ downvoteCount * -1 }} Downvotes

Updated

Date Posted:
1 month ago