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secondary 3 | A Maths
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A bit lost tho.... Please help, thanks.
Date Posted: 4 years ago
Views: 199
Hang on. This one cannot apply ln that way because the denominator is not linear. We change it to power -0.5 and do the usual bring up power by 1 and divide by new power.
Oh sorry. Denominator contains x^2. Wait let me think.
This one cannot be done at your level.
This one cannot be done at your level.
Ok, thanks so much
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I have used an A Level approach (integration by substitution) to solve this integral.
We cannot integrate these type of integrals ordinarily in the O Level, because the term inside the square root, which is 5 + x^2, is not linear. We can't integrate such functions normally, and there are no product and quotient rules to apply for integration as well.
Had the integrand (the function to be integrated) been 1 divided by square root of (5 + x), then we would have been anle to rewrite the expression as (5 + x)^-1/2 before proceeding to integrate normally.
You can try cancelling the square attached to the x and solve for the integral.
We cannot integrate these type of integrals ordinarily in the O Level, because the term inside the square root, which is 5 + x^2, is not linear. We can't integrate such functions normally, and there are no product and quotient rules to apply for integration as well.
Had the integrand (the function to be integrated) been 1 divided by square root of (5 + x), then we would have been anle to rewrite the expression as (5 + x)^-1/2 before proceeding to integrate normally.
You can try cancelling the square attached to the x and solve for the integral.
Date Posted:
4 years ago
Extra info :
https://www.teachoo.com/amp/4999/719/Ex-7.4--2---Integrate-1---root-1---4x2---Class-12-NCERT/category/Ex-7.4/
Alternative ways to integrate : 1 without substitution, 1 with a different kind
https://www.teachoo.com/amp/4999/719/Ex-7.4--2---Integrate-1---root-1---4x2---Class-12-NCERT/category/Ex-7.4/
Alternative ways to integrate : 1 without substitution, 1 with a different kind
Thank you so much
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