Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
junior college 2 | H2 Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
Not sure how to do pls help thanks
Differentiate both sides with respect to x,
siny(dy/dx) = 2x - y - x(dy/dx)
(x + siny)(dy/dx) = 2x - y
dy/dx = (2x - y)/(x + siny)
2 ways to show :
① For the x-axis, y = 0 so dy/dx = 0
For dy/dx = 0, (2x - y)/(x + siny) = 0
Since denominator ≠ 0,
2x - y = 0
y = 2x
Sub y = 2x,
3 - cos2x = -x²
x² + 3 = cos2x
x² + 3 ≥ 3 for all real x since x² ≥ 0 for all real x.
But -1 ≤ cos2x ≤ 1 for all real x.
So x² + 3 ≠ cos2x for all real x.
The two functions will never meet for all real values of x, i.e there are no real values of x that satisfies the equation for dy/dx = 0. So dy/dx ≠ 0
x = 0 on the y - axis.
the gradient of the y-axis is infinity/undefined.
If the tangent to C is parallel to the y-axis, dy/dx is also undefined.
So this means the denominator is 0 since dividing by 0 gives an undefined result.
Then x + siny = 0
siny = -x
sin²y + ysiny + cosy
= (-x)² + y(-x) + cosy
= x² - xy + cosy
= 3 - cosy + cosy (refer to equation of C)
= 3
So this y-coordinate satisfies sin²y + ysiny + cosy = 3
3 - cos 2x = -x^2
for values of x.
See 1 Answer