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secondary 4 | A Maths
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Mc Double
Mc Double

secondary 4 chevron_right A Maths chevron_right Singapore

Looking at -log8 x^3, I really don't know how it became -log4 x^2. Pls show the method. Thank you!

Date Posted: 2 months ago
Views: 29
J
J
2 months ago
log8(x³)

= log4(x³)/log4(8)

= 3log4(x)/log4(4^(3/2))

= 3log4(x)/(3/2log4(4))

= 3log4(x)/(3/2)

= 2log4(x)

= log4(x²)
J
J
2 months ago
Or

log8(x³)

= log4(x³)/log4(8)

= 3log4(x)/log4(4 x 2)


= 3log4(x)/(log4(4) + log4(2))

= 3log4(x)/(log4(4) + log4(4^½) )

= 3log4(x)/(1 + ½)

= 3log4(x)/(3/2)

= 2log4(x)

= log4(x²)

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Eric Nicholas K
Eric Nicholas K's answer
3837 answers (Tutor Details)
1st
It’s sad that the book skips crucial steps at times.
J
J
2 months ago
answer schemes tend to be more brief. Just showing the crucial steps. The manipulation is left to the student