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secondary 4 | A Maths
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Pls help me with part iii. Preparing for o levels. Thank you so much!
Date Posted: 4 years ago
Views: 345
Hi Angelina! The equations in part i and part ii are related since the substitution has been used.
The solutions in part ii and part iii would therefore have the same (real root is u = 2 or 3^x = 2).
We then proceed to solve the equation 3^x = 2 which is solveable by applying logs on both sides to bring the power down.
The solutions in part ii and part iii would therefore have the same (real root is u = 2 or 3^x = 2).
We then proceed to solve the equation 3^x = 2 which is solveable by applying logs on both sides to bring the power down.
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From part ii) , you've shown that the only real solution is u = 2. Since u = 3^x, then 3^x = 2. x = log3(2) = ln2/ln3 (or lg2/lg3) ≈ 0.631 (3.s.f)
Thank you so much!
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