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Question
secondary 3 | A Maths
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I'm not sure how to do part c)
Lg(10^(2x+1)) +lg(7(10^x))= lg26
(2x+1)lg10+(lg7+lg10^x)=lg26
Lg10=1
2x+1 +lg7+x =lg26
3x+1=lg26-lg17
X=lg A
Sub in
3(lgA)+1=lg26-lg17
Leave 1 as lg 10 again
3lgA +lg10=lg (26/7)
3lgA =lg (26/7)-lg10
Lg(A^3)= lg(26/70)
Remove lg from all
A^3= 26/70
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