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Question
primary 6 | Maths
| Geometry
2 Answers Below
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i need help w this
Date Posted: 4 years ago
Views: 233
180° - 100° = 80°
x° and the angle above it are equal.
They are alternate angles since they are between two parallel lines cut by a tranversal line, and are on opposite sides of the transversal.
So that angle is also x°.
Then this angle and the angle adjacent to the 100° angle are also alternate angles for the same reason, but between a different pair of parallel lines from the case above.
So that angle is also x° .
180° - 100° = 80° is based on the property that adjacent angles in a parallelogram add up to 180°.
Therefore x° = 80°
x° and the angle above it are equal.
They are alternate angles since they are between two parallel lines cut by a tranversal line, and are on opposite sides of the transversal.
So that angle is also x°.
Then this angle and the angle adjacent to the 100° angle are also alternate angles for the same reason, but between a different pair of parallel lines from the case above.
So that angle is also x° .
180° - 100° = 80° is based on the property that adjacent angles in a parallelogram add up to 180°.
Therefore x° = 80°
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done
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Hope this helps
Date Posted:
4 years ago
done
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Alexis , I hope this helps (＾ｕ＾)
Date Posted:
4 years ago
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