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Question
primary 6 | Maths
| Speed
2 Answers Below
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Hi. Can someone please help to solve. Thank you!
Travelling at 40/min, ends up late by 3 min.
Difference in time taken = 3 + 1 = 4 min.
So if she travels at 40m/min she will be 4 min slower/behind compared to 50m/min.
She has to walk more 4 more min to arrive at school.
4 min x 40m/min = 160m
This tells us she was 160m away from reaching school. She walked 160m less in the same time compared to 50m/min, where she reached already.
Difference in speed = 50m/min - 40min/min = 10min/min
She walks 10m less every min compared to 50min/min.
160m ÷ 10m/min = 16min
So in 16min, she ended up walking 160m less, was 160m behind/slower, and had 4 min more to walk.
This also tells us at 50m/min, that she reached school in 16 min .
Distance from the point she changed speed to school
= 16min x 50m/min
= 800m
Total distance
= 800m + distance of first 3 minutes she walked
= 800m + 3 x 40m/min
= 800m + 120m
= 920m
See 2 Answers
Time different = 3+1=4mins
Sped different = 50-40= 10 m/min
Distance are same =D
Refer to red pen answer...
Hope you understand the working.