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primary 6 | Maths
| Data Analysis
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Date Posted: 4 years ago
Views: 244
(a)
angle FCB = 60 deg
angle GCD = 180-66-74 = 40 deg
since AB // DC,
angle BCD = 90 deg
so
angle FCD = 90-60 = 30 deg
& angle FCG = angle GCD - angle FCD
= 40 - 30 = 10 deg
(b)
angle CGF
= 180 - angle FCG - angle BFC
= 180 - 10 - 60
= 110 deg
angle GEA
= angle CGF - angle GAE
= 110 - 74
= 36 deg
...
angle FCB = 60 deg
angle GCD = 180-66-74 = 40 deg
since AB // DC,
angle BCD = 90 deg
so
angle FCD = 90-60 = 30 deg
& angle FCG = angle GCD - angle FCD
= 40 - 30 = 10 deg
(b)
angle CGF
= 180 - angle FCG - angle BFC
= 180 - 10 - 60
= 110 deg
angle GEA
= angle CGF - angle GAE
= 110 - 74
= 36 deg
...
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Hope this helps
Date Posted:
4 years ago
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