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Question
primary 6 | Maths
| Geometry
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Date Posted: 4 years ago
Views: 369
angle ACD = angle AED = 62 deg
since triangle ABC is isosceles,
angle ABC = 62/2 = 31 deg
...
since triangle ABC is isosceles,
angle ABC = 62/2 = 31 deg
...
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Exterior angle of isosceles triangle ABC = 62 degree = sum of 2 interior opp angle of isos.triangle ABC
Date Posted:
4 years ago
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Ext angle of isos triangle ABC =62 degree = sum of 2 int. Opp. Angle . Hence Angle ABC = 62/2 = 31 degree.
Date Posted:
4 years ago
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