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primary 6 | Maths | Speed
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Jo
Jo

primary 6 chevron_right Maths chevron_right Speed chevron_right Singapore

Please help solve these 2 questions. Thx!

Date Posted: 4 years ago
Views: 385

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Time taken for jack: 48/80 = 36 mins
Time take for Ryan: 36+10= 46 mins
Distance for Ryan: (in hours) 46/60 x 60 = 46km

In order of Ryan to reach at the same time, he needs to cover 46km in 36mins.
36mins=36/60 hours
= 0.6hours
Average speed = 46/0.6
= 76.67km/h
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Shawn
Shawn's answer
82 answers (A Helpful Person)
1st
Jo
Jo
4 years ago
Thank you! Do you know the answer for qn 41 as well?
Shawn
Shawn
4 years ago
Working on it right now. Did you learn basic algebra?
Jo
Jo
4 years ago
Yes I did
J
J
4 years ago
You can also leave the answer in the exact form 76⅔ km/h
Jo
Jo
4 years ago
Thanks!
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Shawn
Shawn's answer
82 answers (A Helpful Person)
This is the algebra way of doing it.
Shawn
Shawn
4 years ago
You don’t have to find the speed of Ethan. After finding that Ethan needs to take D/48 + 1/6 to cover D/2 of the journey, in order for him to complete the full journey D, he needs (D/48 + 1/6) x 2 = D/24 + 1/3. Then from Daniel’s time taken which is D/24, you can conclude that Ethan needs 1/3 hour more to complete which equals to 20 mins.
Daniel was 4km ahead of Ethan when Ethan reached the halfway mark.

Since Daniel's speed was 24km/h, time he took to travel this 4km = 4km ÷ 24km/h
= 1/6 h = 10 minutes

Since Daniel took 10 minutes to travel this 4 km, this means that he actually reached the halfway mark 10 minutes before Ethan did.

So Ethan takes 10 more minutes to reach the halfway mark than Daniel.

So for the whole journey, which is twice of that distance,

Ethan will take 10min x 2 = 20 more minutes to finish it than Daniel


11.50 + 00.20 = 11.70 = 12.10

So Ethan will finish at 12.10pm
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J
J's answer
1022 answers (A Helpful Person)