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secondary 3 | A Maths
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secondary 3 chevron_right A Maths chevron_right Singapore

i dont know how to start

Date Posted: 4 years ago
Views: 196
J
J
4 years ago
You need to change logy(81) first by conversion of the y from base to on top.


log9(y²) = 3 + logy(81)

Theres a log9(y)² on the left so you have to change the right side's terms into that form.

2log9(y) = 3 + logy(9²)

2log9(y) = 3 + 2logy(9)

2log9(y) = 3 + 2 (1/log9(y) )

2log9(y) = 3 + 2/log9(y)

Multiply by log9(y) to get rid of the denominator,

2(log9(y))² = 3log9(y) + 2

Now you can see that the equation is in the form of 2u² = 3u + 2
J
J
4 years ago
Alternatively, you can change the left hand side into the form logy(9) instead.


log9(y²) = 3 + logy(81)

2log9(y) = 3 + logy(9²)

2(1/logy(9) ) = 3 + 2logy(9)

Multiply by logy(9),

2 = 3logy(9) + 2( logy(9) )²

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