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Question
secondary 3 | A Maths
4 Answers Below
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Pls help me tell part (b). Thank you
Date Posted: 4 years ago
Views: 206
(b)
5cot x + 3 = 2 + 3cot x
=> 2cot x = -1
=> cot x = -0.5
=> 1/tan x = -0.5
=> tan x = -2 [ 2nd & 4th quads ]
=> x = 180-63.4 or x = 360-63.4
=> x = 116.6 deg or x = 296.6 deg
...
5cot x + 3 = 2 + 3cot x
=> 2cot x = -1
=> cot x = -0.5
=> 1/tan x = -0.5
=> tan x = -2 [ 2nd & 4th quads ]
=> x = 180-63.4 or x = 360-63.4
=> x = 116.6 deg or x = 296.6 deg
...
See 4 Answers
Thank you!!
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Nicole, here are my relevant guidelines for these questions.
Date Posted:
4 years ago
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Question (b) appears on the left column of my answers. I have written down my answers without any quadrant diagrams so you may use the other tutor's quadrant diagrams.
Date Posted:
4 years ago
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These answers are not for any of your posted questions, but for question (a), the workings are very similar in idea to my answer for part (e) on the left column.
Let me know if you need a clearer explanation.
Let me know if you need a clearer explanation.
Date Posted:
4 years ago
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