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Question
primary 5 | Maths
| Angles & Geometry
2 Answers Below
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Date Posted: 4 years ago
Views: 284
BCE = BCD - ECD
= 90° - 40°
= 50°
GCB = GCE - BCE
= 90 - 50°
= 40°
x = JCH - GCB - GCH
= 90° - 40° - 27°
= 23°
= 90° - 40°
= 50°
GCB = GCE - BCE
= 90 - 50°
= 40°
x = JCH - GCB - GCH
= 90° - 40° - 27°
= 23°
See 2 Answers
done
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Hope this helps
Date Posted:
4 years ago
done
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Sorry, amended correct answer
Date Posted:
4 years ago
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