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primary 5 | Maths | Angles & Geometry
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Yong en
Yong En

primary 5 chevron_right Maths chevron_right Angles & Geometry chevron_right Singapore

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Date Posted: 2 months ago
Views: 12
J
J
2 months ago
BCE = BCD - ECD
= 90° - 40°
= 50°

GCB = GCE - BCE
= 90 - 50°
= 40°

x = JCH - GCB - GCH
= 90° - 40° - 27°
= 23°

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AC Lim
Ac Lim's answer
3075 answers (A Helpful Person)
1st
Hope this helps
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Eka Wulan Oktavia
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8 answers (Tutor Details)
Sorry, amended correct answer