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primary 5 | Maths
| Fractions
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P5 Math .Help with working and solution
Date Posted: 4 years ago
Views: 302
Brandon have 7/7
3/7 = 6 toys + 6 erasers
Remaining =4/7
1/7 = 10 cards (1/4 of 4/7)
Cost
1 card = 1 eraser + $0.30
10 cards = 10 eraser + $3.00 (1/7 of Brandon money)
1/7 = 10u + $3.00
eraser = 1u,
toys = 7u,
6 erasers = 6u
6 toys = 42u
6 erasers + 6 toys = 42 + 6 = 48u
3/7 ---> 48u
1/7 = 48u/3 = 16u
10u+ $3.00 = 16u
6u = $3.00
1u = $3.00 / 6
1u= $0.50
Each toy= 7u = 7 x $0.50 = $3.50
3/7 = 6 toys + 6 erasers
Remaining =4/7
1/7 = 10 cards (1/4 of 4/7)
Cost
1 card = 1 eraser + $0.30
10 cards = 10 eraser + $3.00 (1/7 of Brandon money)
1/7 = 10u + $3.00
eraser = 1u,
toys = 7u,
6 erasers = 6u
6 toys = 42u
6 erasers + 6 toys = 42 + 6 = 48u
3/7 ---> 48u
1/7 = 48u/3 = 16u
10u+ $3.00 = 16u
6u = $3.00
1u = $3.00 / 6
1u= $0.50
Each toy= 7u = 7 x $0.50 = $3.50
See 1 Answer
done
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Hope this helps
Date Posted:
4 years ago
Thanks
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