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secondary 3 | A Maths
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Linear law chapter
Date Posted: 4 years ago
Views: 283
x²y = -by +ax²
x²y + by = ax²
y(x² + b) = ax²
y = ax² / (x² + b)
y = a[x² / (x² + b)]
y = a[(x² + b - b) / (x² + b)]
y = a[1 - b/(x² + b)]
y = a - ab/(x² + b)
Y = y , X = 1/(x² + b) ,
m = -ab , c = a
...
x²y + by = ax²
y(x² + b) = ax²
y = ax² / (x² + b)
y = a[x² / (x² + b)]
y = a[(x² + b - b) / (x² + b)]
y = a[1 - b/(x² + b)]
y = a - ab/(x² + b)
Y = y , X = 1/(x² + b) ,
m = -ab , c = a
...
See 1 Answer
done
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clear
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Here is one possible form (of I believe at least six possible forms) which is linear.
Date Posted:
4 years ago
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