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secondary 4 | A Maths
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Date Posted: 5 years ago
Views: 208
*note:
1. log₃ 14 - log₃ 2 = log₃ (14/2) = log₃ 7
2(a) ln e = 1
2(b) ln e² = 2ln e = 2
3. log₃ 343 = log₃ 7³ = 3log₃ 7
hence,
(log₃ 14 - log₃ 2)/(ln e²)
= (log₃ 7)/2
(ln e)²/log₃ 343
= (1)²/3log₃ 7
= 1/3log₃ 7
(log₃ 14 - log₃ 2)/(ln e²) x [(ln e)²/log₃ 343]
= (log₃ 7)/2 x 1/3log₃ 7
= 1/6
...
1. log₃ 14 - log₃ 2 = log₃ (14/2) = log₃ 7
2(a) ln e = 1
2(b) ln e² = 2ln e = 2
3. log₃ 343 = log₃ 7³ = 3log₃ 7
hence,
(log₃ 14 - log₃ 2)/(ln e²)
= (log₃ 7)/2
(ln e)²/log₃ 343
= (1)²/3log₃ 7
= 1/3log₃ 7
(log₃ 14 - log₃ 2)/(ln e²) x [(ln e)²/log₃ 343]
= (log₃ 7)/2 x 1/3log₃ 7
= 1/6
...
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Date Posted:
5 years ago
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