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secondary 4 | A Maths
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secondary 4 chevron_right A Maths chevron_right Singapore

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Date Posted: 4 years ago
Views: 186
snell
Snell
4 years ago
*note:

1. log₃ 14 - log₃ 2 = log₃ (14/2) = log₃ 7

2(a) ln e = 1

2(b) ln e² = 2ln e = 2

3. log₃ 343 = log₃ 7³ = 3log₃ 7

hence,
(log₃ 14 - log₃ 2)/(ln e²)
= (log₃ 7)/2

(ln e)²/log₃ 343
= (1)²/3log₃ 7
= 1/3log₃ 7



(log₃ 14 - log₃ 2)/(ln e²) x [(ln e)²/log₃ 343]

= (log₃ 7)/2 x 1/3log₃ 7

= 1/6


...

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Eric Nicholas K
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