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Question
secondary 4 | E Maths
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Date Posted: 4 years ago
Views: 205
I write down here first
3/a = 2/b + 1/c
2/b = 3/a - 1/c
2/b = (3c - a) / ac
b/2 = ac / (3c - a)
b = 2ac / (3c - a)
3/a = 2/b + 1/c
2/b = 3/a - 1/c
2/b = (3c - a) / ac
b/2 = ac / (3c - a)
b = 2ac / (3c - a)
Will start writing most likely past 5 pm on a bit by bit basis
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done
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hope this helps! feel free to clarify :D
Date Posted:
4 years ago
Thank for help
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