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secondary 3 | A Maths
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I just started Linear Law today and I’m a little stuck, would mean a lot if someone helped (:
Date Posted: 4 years ago
Views: 225
what's the instruction?
Y = 1/y
X = 1/x
gradient m = b/a
y-intercept = c/a
Y = 1/y
X = 1/x
gradient m = b/a
y-intercept = c/a
In the linear equation Y=mX+c,
Y can be in any form involving only the variable of y. Meaning Y cannot contain x.
Likewise, X can be in any form involving only the variable of x and cannot contain y.
m and c cannot contain y or x variable as they must be constants. m and c can be in any form. However, m must be a factor of X, and c must be a term by itself.
Y can be in any form involving only the variable of y. Meaning Y cannot contain x.
Likewise, X can be in any form involving only the variable of x and cannot contain y.
m and c cannot contain y or x variable as they must be constants. m and c can be in any form. However, m must be a factor of X, and c must be a term by itself.
You mean m is a “coefficient” of X.
I will write up the explanations later.
I will write up the explanations later.
To be more specific, yes. Good you got it. 'Factor' is a more general though. Keep it up :)
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This one is not for this question, but the left half of my writings contains an explanation for the linear law. I will next write up the case for this example.
Date Posted:
4 years ago
Thank you so, so much! I really appreciate that you explained Linear Law, and after these few days, i am finally better at it! Once again, really appreciate it :)
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One possible way
Date Posted:
4 years ago
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Can also be done this way, with different expressions for Y, X, m and c, but all of these different forms are linear.
There are a few more forms, but I will not do them here. You can play around with the terms and obtain the remaining ones.
Do not be surprised if Y contains only x and X contains only y. In linear law, this is perfectly acceptable.
There are a few more forms, but I will not do them here. You can play around with the terms and obtain the remaining ones.
Do not be surprised if Y contains only x and X contains only y. In linear law, this is perfectly acceptable.
Date Posted:
4 years ago
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