## Ask Singapore Homework?

Upload a photo of a Singapore homework and someone will email you the solution for free.

## Question

primary 6 | Maths
| Geometry

** One Answer Below **

Anyone can contribute an answer, even non-tutors.

**Answer This Question**

Can anyone pls help me ASAP thanks

= 15 x 1.8l

= 27l

27l = 27 x 1000cm³ = 27000cm³

Height of water in the tank

= Volume of water ÷ length of tank ÷ width of tank

= 27000cm³ ÷ 50cm ÷ 30cm

= 18cm

b)

Increase in height of water in Tank P per min

= 18cm ÷ 15min

= 1.2cm per min

6l = 6 x 1000cm³ = 6000cm³

Increase in height of water in Tank Q per minute

= increase in volume of water per minute ÷ length of Tank Q ÷ width of Tank Q

= 6000cm³ per min ÷ 50cm ÷ 40cm

= 3cm per min

So compared to Tank P,

3cm - 1.2cm = 1.8cm

Height of water in Tank Q increases 1.8cm more than in Tank P per minute.

At 10.15am, height of water in Tank P is 18cm, when filling of Tank Q had just started(which is as good as saying the height of water is 0cm. )

So as every minute passes, the difference in the water height between the 2 tanks is getting smaller by 1.8cm

18cm ÷ 1.8cm per minute = 10minutes

10 minutes is needed for height of water in Tank Q to become the same as Tank P.

1015 + 0010 = 1025

It will be 10.25am when the water level is the same.

### See 1 Answer

*done*{{ upvoteCount }} Upvotes

*clear*{{ downvoteCount * -1 }} Downvotes